<em>Answer:</em>
<em>{</em><em>c,</em><em>d,</em><em>e}</em>
<em>Solution</em><em>,</em>
<em>P </em><em>n </em><em>Q </em><em>n </em><em>R</em>
<em>=</em><em>{</em><em>a,</em><em>b,</em><em>c,</em><em>d,</em><em>e}</em><em> </em><em>n </em><em>{</em><em> </em><em>a,</em><em>c,</em><em>e,</em><em>d,</em><em>t}</em><em> </em><em>n </em><em>{</em><em>t,</em><em>d,</em><em>c,</em><em>b,</em><em>e}</em>
<em>=</em><em>{</em><em>c,</em><em>d,</em><em>e}</em>
<em>In </em><em>case </em><em>of </em><em>intersection</em><em>,</em>
<em>we </em><em>have </em><em>to </em><em>list </em><em>the </em><em>common </em><em>elements </em><em>which</em><em> </em><em>are </em><em>present </em><em>in </em><em>all </em><em>sets.</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em> </em>
Answer:
5/11
Step-by-step explanation:
7+5+10=22
fraction of grey t-shirts would be 10/22
simplify it and u get 5/11
∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
Learn more about similar triangles here:
brainly.com/question/25882965
#SPJ1
13%-23% and yeah some like that I’m not 100 percent I’m correct
Answer:
1/2
Step-by-step explanation:
