Question

How many moles are 3.21 x 1028 molecules of N2

Answer 1

Hello!

$\large\boxed{5.33*10^{4} moles}$

Begin by converting $3.21 * 10^{28}$ molecules to moles using Avogadro's number:

$3.21*10^{28} moles* \frac{1 mol}{6.02*10^{23} moles} = \frac{3.21*10^{28} }{6.02*10x^{23} }moles$

Simplify:

$\frac{3.21*10^{28} }{6.02*10x^{23} }=0.53*10^{5} = 5.33*10^{4}$

Therefore, there are $5.33*10^{4}$ moles in $3.21*10^{28}$ molecules of $N_{2}$.