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luda_lava [24]
3 years ago
6

Can someone help me with this? No links please

Mathematics
2 answers:
Sphinxa [80]3 years ago
6 0

Answer:

3) (4x-9)(4x+9)

Step-by-step explanation:

Westkost [7]3 years ago
5 0

Answer:

(3) (4x - 9)(4x + 9)

Step-by-step explanation:

4x times 4x will give you 16x^2, and 9 times 9 is 81, but you need to have one of the nines negative to give you the -81.

You needed the square root of 16 and the square root of x^2, then the square root of 81.

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Answer:The number of angles & sides is always the same.

Step-by-step explanation:

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Answer is 28

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4 years ago
Which of the following is a polynomial?
butalik [34]

Answer:

B

Step-by-step explanation:

8x^2+x+3 follows the rules of being a polynomial due to the three terms being added to each other, and that they are in descending order.

6 0
3 years ago
Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
Match each equation with its graph. Use the graph of<br> y= x, shown in red, to help.
My name is Ann [436]

Answer:

igggg

Step-by-step explanation:

hfghggghvvhhhgghu

3 0
3 years ago
Read 2 more answers
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