The number of triangles is n-2
n= number of sides
8-2= 6 triangles
if applying this you won't have to draw any diagonals to
find the number of triangles just subtract 2 from the number of sides
hope this helps
Answer:
44x + 54
Step-by-step explanation:
The nth term of an arithmetic sequence is given by :
Tn = a + (n - 1)d
d = common difference = T2 - T1
d = T2 - T1
a = first term = - x + 9
d = 4x + 14 - (-x + 9)
d = 4x + 14 + x - 9
d = 5x + 5
The 10th term:
T(10) = (-x + 9) + (10 - 1)*(5x + 5)
T(10) = - x + 9 + 9(5x + 5)
T(10) = - x + 9 + 45x + 45
T(10) = 44x + 54
Hence, the 10th term is 44x + 54
It should be,
4x-8=2x-10 because you substitute that for y.
Now you do,
4x-2x because you do the opposite of the positive 2x as you bring it to the other side.
That is,
2x-8=10 now you bring the 8 to the other side.
2x=10+8 I added it because I do the opposite and it is a negative 8 so I add.
2x+18 now divide
x=9 that's the answer.
Whoever put this problem is smarttttttttttt
