Question

Two investments totallng $47,500 produce an annual income of $3000. One investment ylelds 9% per year, while the other yields 6% per year. How much is invested at each rate?​

Answer 1

Answer:

The correct answer is "$5000".

Step-by-step explanation:

The given values are:

Two investments totaling,

= $47,500

Annual income,

= $3000

One investment yields per year,

= 9%

Other yield,

= 6%

Let,

• The amount invested in 9% will be "x".
• The amount invested in 6% will be "$47,500-x$".

Now,

⇒  $0.09x+0.06(47,500-x)=3000$

⇒        $0.09x+2850-0.06x=3000$

⇒                     $0.03x+2850=3000$

⇒                                $0.03x=150$

⇒                                       $x=\frac{150}{0.03}$

⇒                                       $x=5000$