What is the domain and range of y = 4x + 1?

I need help with graph the question is .

il63 [147K]

(-9,1) (-7,2) (-5,3)

5 0

3 years ago

All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessarily the same as the weigh

BaLLatris [955]

Answer:

The largest possible weight of flour is 11.25 pounds.

Step-by-step explanation:

To start with, we will assume that the weight of 1 sack of sugar = x pounds

We will also assume that the weight of 1 sack of flour = y pounds

So, the weight of 2 sacks of sugar = 2 * (x) = 2x

Same thing goes for the weight of 3 sacks of flour = 3 * (y) = 3y

Supposing that the weight of (2 sacks of sugar + 3 sacks of flour) ≤ 40 pounds

= 2x + 3y ≤ 40............ we'll call that equation 1.

Also, suppose that the weight of ( 1 sack of flour) ≤ 2 sacks of sugar + 5 pounds

= y ≤ 2x + 5........................ we'll call that equation 2

Therefore, we'll solve for the values of x and y in the two equations and we will get:

2x + 3y ≤ 40

y ≤ 2x + 5

Now, substitute the value of y into equation 1

2x + 3y ≤ 40 ⇒ 2x + 3(2x +5) =40

⇒ 2x + 6x + 15= 40

⇒ 8x + 15 = 40

⇒ 8x = 25

⇒ x = 25/8

⇒ x = 3.12

x cannot be more than 3.12 pounds, so we solve for y

Putting the value of x into equation 2, we'll get

⇒ 2y + 5 = 2(3.12) + 5

⇒ y = 11.25 pounds.

So, n cannot be more than 11.25 pounds

8 0

3 years ago

What can be considered as a real-life example of a Linear Function?

adell [148]

Answer:Phynotomas diagram

Step-by-step explanation:

thank you

7 0

3 years ago

Find the perimeter of the object Help step by step please!

aliina [53]

Answer:

29.42 units

Step-by-step explanation:

1) Find the perimeter around the semi-circle

To do this, we find the circumference of the circle using the given diameter:

$C=\pi d$ where d is the diameter

Plug in 6 as the diameter

$C=\pi (6)\\C=6\pi$

Divide the circumference by 2

$\frac{6\pi }{2} \\= 3\pi$

Therefore, the perimeter around the semi-circle is 3π units.

2) Find the perimeter around the rest of the shape

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those vertical sides facing the right add up to 6. We also know that all of those horizontal sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape

$20+3\pi \\= 20+9.42\\= 29.42$

Therefore, the perimeter of the shape is approximately 29.42 units.

I hope this helps!

3 0

3 years ago

How much does each one equal?

nadya68 [22]

Answer:

need more information

4 0

3 years ago