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kondor19780726 [428]
2 years ago
10

Using complete sentences, explain how proximity to major rivers influenced the location of early cities.

Biology
2 answers:
My name is Ann [436]2 years ago
6 0

Answer:

Major rivers were the main location for many cities, because of the commodities it brought. Rivers supplied the nations with water and food, for example fishes. Additionally, rivers also helped with the irrigation system for crops, with the cattle, and also worked as a way of transportation to other cities with canoes. The bigger the river the more it nourishes and helps the cities to grow. Not also what was mentioned before, but rivers were more reliable than rain. For example if a city was establishes in a middle of the desert, the citizens had to rely on the rain, that could come every day or could come once every month, to supply water for the whole civilization, but with cities near the river, especially mayor rivers, had access to water constantly.

Explanation:

lesya692 [45]2 years ago
5 0

Answer:

Locations along rivers meant faster travel upstream and downstream to rule territories. The city became the place where the ruler or rulers lived together in a stationary spot. The city's location along early rivers encouraged stronger government, which in turn encouraged stronger cities.

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How many grams of the compound in the figure above are required to make 1 liter of a 0.5 M solution? (Note: The atomic masses, i
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Answer:

This question is incomplete as there is no figure in the question but the compound in the figure is Ethanoic acid (CH3COOH). Hence, we can calculate the mass.

The answer is: 30grams

Explanation:

According to the question, the volume of the compound (CH3COOH) is 1litre while the molar concentration is 0.5M

Molarity or Molar concentration is calculated using the formula:

M= n/V

Where; M= Molarity (M) = 0.5M

n= number of moles (mol)

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Hence, number of moles (n) = M × V

n = 0.5 × 1

n = 0.5 moles.

To calculate the mass in grams of CH3COOH, we say;

Number of moles (n) × molar mass (MM)

Since atomic mass for (C= 12, H= 1 and O=16)

Molar mass of CH3COOH:

= 12 + 1(3) + 12 + 16 + 16 + 1

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Explanation:

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