Answer:
C
Step-by-step explanation:
Using the rule of radicals/ exponents
⇔ ![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Given
=
→ C
Answer:

Step-by-step explanation:
Let <em>P(A) </em>be the probability that goggle of type A is manufactured
<em>P(B) </em>be the probability that goggle of type B is manufactured
<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.
According to the question,
<em>P(A)</em> = 30%
<em>P(B)</em> = 70%
<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.
P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.
will be the probability that a goggle is of type A and is returned within 10 days of its purchase.
will be the probability that a goggle is of type B and is returned within 10 days of its purchase.





If a goggle is returned within 10 days of its purchase, probability that it was of type B:


So, the required probability is 
A) it is left skewed
B) the median is 5
C) the mean is 5.15
D) the mean would be more affected (a change of 1.05 versus a change of 0.5).
The majority of the data is to the right of the graph; this means it is left skewed.
To find the median, write all of the data values out:
2, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7
The middle value is 5.
We find the sum of this set of values and divide by 13, the number of data points, to find the mean:
2+3+4+4+5+5+5+6+6+6+7+7+7 = 67/13 = 5.15
If we added an additional data value at 20, the new median would be 5.5. The new mean would be (67+20)/14 = 6.2. The mean changes more than the median.
Yes this is the right answer