She has 52 card all together so she has a probability of drawing on the first draw 4 L's or R's because their are two sets of alphabet cards. So that is 4/52 or 1/13 to the lowest term. Second turn she only has 51 cards to draw from and still has 4 L's and R's so that would be 4/51 and on the third try she has only 50 cards left so that would be 4/50 or 2/25 to the lowest term. Now multiply all three factions 1/13 x 4/51 x 2/25 = 8/16575 meaning out of the three draws she has a probability of getting a L or R, 8 out of 16575 each draw.
<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>parallel</em><em>.</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
Option A 90,68
Step-by-step explanation:
see the attached figure to better understand the problem
The figure shows a kite
we know that
A kite properties include
1) two pairs of consecutive, congruent sides
2) congruent non-vertex angles
3) perpendicular diagonals
Find the measure of angle 1
we have that
----> by the diagonals are perpendicular
Find the measure of angle 2
we know that
triangle AEB is congruent with triangle CEB
so
In the right triangle EAB
----> by complementary angles in a right triangle
so
therefore
Answer:
g or h whichever u think is best
Step-by-step explanation:
Given: line segment AB // to line segment CD, ∠B ≅∠D and line segment BF ≅ to line segment ED. Prove: Δ ABF ≅ Δ CED.
Follow the matching numbers on the statement versus reason chart.
Statement:
1. line segment AB // to line segment CD.
2. ∠B ≅∠D
3. line segment BF ≅ to line segment ED.
4. ∠A ≅∠C
5. Δ ABF ≅ Δ CED
Reason:
1. Given
2. Given
3. Given
4. Alternate interior angles are congruent.
5. Corresponding parts of congruent triangles are congruent.
