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3 years ago

Solve for x and y.... plzzzz

Mathematics

2 answers:

Ierofanga [76]3 years ago

3 0

Answer:

x = 3

y = 1/2

Step-by-step explanation:

${9}^{2y} \times {2}^{x} = 72 \\ \\ {9}^{2y} \times {2}^{x} = 9 \times 8 \\ \\ {9}^{2y} \times {2}^{x} = {9}^{1} \times {2}^{3} \\ \\ equating \: like \: terms \: on \: both \: sides \\ \\ {2}^{x} = {2}^{3} \\ \red { \bold{\implies x = 3}} \\ \\ {9}^{2y} = {9}^{1} \\ \implies \: 2y = 1 \\ \purple{ \bold{\implies \: y = \frac{1}{2} }}$

LenKa [72]3 years ago

3 0

Step-by-step explanation:

good..............................

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A man and a woman agree to meet at a certain location about 12:30 pm. If the man arrives at a time uniformly distributed between

dimaraw [331]

Explanation.

The question is incomplete. However, the complete part of the question simply states that: What is the probability that the man arrives first?

Answer:

Therefore, we can say that the probability that the man will arrive first is half that is 1/2 while the probability that no one will wait more than five times is 1/6

Step-by-step explanation:

We assume the man and the woman arrive at 12:X and 12:Y respectively (1:00 is 12:60). Also, the space of X and Y are [15, 45] and [0, 60] respectively, and fₓ (x) ≡ 1 / (45 − 15) = 1/30, fy (y) ≡ 1 / (60 − 0) = 1 / 60.

So the joint pdf of X and Y is

f(x, y) = 1 / 30 x 1 / 60

= 1 / 1800

where ( x , y ) ∈ [15, 45] × [0, 60].

Consequentially,

P(| X − Y | ≤ 5) = ∫ Iim (45)(15) ∫ lim (x+5)(x-5) f (x,y)dydx

= 1 / 1800 ∫ Iim (45)(15) y | ₓ₋₅ˣ⁺⁵ dx

= 30 x 10 / 1800

300 / 1800

= 1 / 6

Hence,

P( X < Y ) = ∫ Iim (45)(15) ∫ lim (60)(x) f (x,y) dydx

= 1 / 1800 ∫ Iim (45)(15) y | ⁶⁰ₓ dx

= 1 / 1800 ∫ Iim (45)(15) ( 60 - x ) dx

= 60 x − x ²/2 ÷ 1800 ║⁴⁵₁₅

= 1 / 2

8 0

3 years ago

Read 2 more answers

Eight toymakers each carved 25 blocks<br> and 15 cars. How many toys did they<br> carve in all?

taurus [48]

Answer: 320 toys

Step-by-step explanation:

We can use an expression to solve this question.

8 (25 + 15)

8 (40)

320

4 0

3 years ago

I need help with this question, pls put step by step

Scrat [10]

Answer:

150 degrees and 30 degrees

Step-by-step explanation:

Let's say the measure of the angle is x. This angle is 5 times that of its supplementary, supplementary angles will add up to 180 degrees. So we have an equation of x = 5(180-x). Solve this equation for x

x = 5(180-x)

x = 900 - 5x

6x = 900

x = 150 degrees, this is the value of one angle

The other angle is 180-x = 180-150 = 30 degrees

4 0

3 years ago

Find the zero of each function and state the multiplicity of each zero. Please show all steps.

vodka [1.7K]

Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

Step-by-step explanation:

1. y=(x+3)^3

$y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3$

Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1)

$y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.$

Zeros: x=2 multiplicity 2; x=1 multiplicity 1

3. y=(2x+3)(x-1)^2

$y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.$