Since there are 22 participants all in all. The possible combinations of the two picked for practice first is,
22C2 = 231
The probability of picking one from each gender will be solved through the calculation below.
(10C1)x(12C1) / 231 = 40/77
In percentage, the answer would be approximately 52%. Thus, the answer is the first choice.
Can anyone else figure this out
Answer:
the solutions are c because, when we say x +7=81 that will give us 74 which is there on c
Answer:
C
Step-by-step explanation:
We will assume that each of their cups holds exactly 1 cup of liquid. Let <em>m</em> represent milk and <em>c</em> represent coffee.
Jane = 1/2<em>m</em> + 1/2<em>c</em> to represent 1/2 milk and 1/2 coffee
Jean, June, and Joan = 3(1/4<em>m</em> + 3/4<em>c</em>) [they all 3 like the same ratio, so multiply the expression by 3], to represent 1/4 milk and 3/4 coffee
Ian = 1<em>c </em>(since he likes black coffee, his entire 1-cup dish of coffee will be coffee)
Adding these together we have:
1/2<em>m</em> + 1/2<em>c</em> + 3(1/4<em>m</em> + 3/4<em>c</em>) + 1<em>c</em>
= 1/2<em>m</em> + 1/2<em>c</em> + 3/4<em>m</em> + 9/4<em>c</em> + 1<em>c</em>
Find a common denominator:
= 2/4<em>m</em> + 2/4<em>c</em> + 3/4<em>m</em> + 9/4<em>c</em> + 1<em>c</em>
Convert the 1 whole to a fraction:
= 2/4<em>m</em> + 2/4<em>c</em> + 3/4<em /><em>m</em> + 9/4<em>c</em> + 4/4<em>c</em>
Combine your <em>m</em>'s:
= 5/4<em>m</em> + 2/4<em>c</em> + 9/4<em>c</em> + 4/4<em>c</em>
Combine your <em>c</em>'s:
= 5/4<em>m</em> + 15/4<em>c</em>
We know there is 4 times as much coffee as milk. Looking at the two fractions we have left, we can see that 15/4<em /> = 3(5/4). We would expect to see 4(5/4), since there is 4 times as much coffee. That means we have 5/4 or 1 1/4 of the liquid left.
