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2 years ago

5

Find the value of x rounded to the nearest tenth.

1 answer:

soldier1979 [14.2K]2 years ago

7 0

Step-by-step explanation:

everything can be found in the picture

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Use the vertex formula to find the vertex of the quadratic function f(x)=-x^2+6x-10

mixer [17]

Answer:

15

Step-by-step explanation:

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2 years ago

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5x-2y=11 and 3x+4y=4<br>Find the value of x and y in equation.

nadya68 [22]

5x-3y=11---(1)
3x+4y=4---(2)

(1)×3 and (2)×5

15x-9y=33-(3)
15x+20y=20-(4)

Subtract both

$\\ \sf\longmapsto -29y=13$

$\\ \sf\longmapsto y=\dfrac{-13}{29}$

Put in eq(1)

$\\ \sf\longmapsto 5x+\dfrac{-117}{29}=11$

$\\ \sf\longmapsto 5x=11+\dfrac{117}{29}=\dfrac{261+117}{29}=\dfrac{278}{29}$

$\\ \sf\longmapsto x=\dfrac{278}{145}$

7 0

2 years ago

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If a(x)=2x-4 and b(x) =x+2, which of the following expressions produces a quadratic function?

ZanzabumX [31]

Answer:

$(ab)(x)$

Step-by-step explanation:

The complete question in the attached figure

we have

$a(x)=2x-4\\b(x)=x+2$

we know that

(ab)(x) is equal to the product of a(x) and b(x)

so

$(ab)(x)=(2x-4)(x+2)$

Applying distributive property

$(ab)(x)=2x(x)+2x(2)-4(x)-4(2)$

$(ab)(x)=2x^2+4x-4x-8$

$(ab)(x)=2x^2-8$

This is a quadratic equation

The other expressions not produce a quadratic equation

5 0

3 years ago

Can you create a pattern with the rule n*2+1

Citrus2011 [14]

3, 5, 7, 9, 11, etc.

4 0

2 years ago

Express with radical signs instead of fractional exponents. Rationalize the denominator.

CaHeK987 [17]

$x^{\frac{1}{2}} = \sqrt[2]{x}$ and $3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}}$ so

$3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x} = \frac{\sqrt{x}}{\sqrt{3}}$

and you rationalize denominator by multiplying numerator and denominatr by $\sqrt{3}$ so that gives--

$\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}$

Your answer is $\frac{\sqrt{3x}}{3}$

5 0

2 years ago