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Setler [38]
3 years ago
8

Describe the changes that occur inside a helium balloon as it rises from sea level

Physics
1 answer:
zheka24 [161]3 years ago
8 0

Answer:

The balloon expands in the number of particles per cubic centimeter decreases. This happens because as it expands there is a decrease in the density of area. The Dead Sea is a solution that is so dense that you easily float on it.

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Answer:

Explanation:

1.  V_{x} = V_{0} * cos\alpha ⇒ 16*cos32 ≈ 13.6 m/s (13.56)

2. V_{y} = V_{0} * sin\alpha ⇒ 16* sin32 ≈ 9.4 m/s

3. y_{max} = \frac{v_{0}^2*sin^2\alpha}{2g}= \frac{16^2*sin^232}{2*9.8} (the g (gravity) depends on the country but i'll take the average g which is 9.2m/s^2)

y_{max} ≈ 3.6677+1.5 ≈ 5.2m

4.  x_{max} = \frac{v_{0}^2*sin(2\alpha)}{g}=\frac{16^2*sin(2*32)}{9.8} ≈ 23.5m (23.47)

5. -

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