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3 years ago

Can you answer this math homework? Please!

Physics

1 answer:

notka56 [123]3 years ago

5 0

$\large \mathfrak{Solution : }$

Average speed :

$\boxed{ \dfrac{distance \: \: covered}{total \: \: time \: \: taken} }$

$\dfrac{100}{8}$

$12.5 \: \: m/s$

The horizontal (flat) line on a Distance - time graph shows that the body is at rest because the value of Distance (on y - axis ) is same for increasing time ( on x - axis ), it basically shows that the object is at the same position with the change in time.

therefore, correct option is :

$a. \: \: the \: \: object \: \: is \: \: not \: \: moving$

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2 years ago

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3 years ago

A heavy meterstick has a mass of 1 kg. When the meterstick is thrown like a spear past you, you measure its momentum to be 2mv.

CaHeK987 [17]

Answer:

Its length is measured to be 0.5 m

Explanation:

From theory of relativity (mass variation), we know that:

m = mo/√(1-v²/c²)

Where, m = relative mass

and, mo = rest mass

The momentum of stick while moving, will be:

P = mv

but, it is given in the form of rest mass as:

P = 2(mo)v

thus, by comparison;

2(mo)v = mv

using value of m from theory of relativity;

2(mo)v = (mo)v/√(1-v²/c²)

√(1-v²/c²) = 1/2 ______ eqn(1)

Now, for relativistic length (L), we have the formula from same theory of relativity;

L = (Lo)√(1-v²/c²)

The rest length (Lo) of meter stick is 1 m, and the remaining term on right side √(1-v²/c²), known as Lorentz Factor, can be given by eqn (1), as equal to 1/2.

Thus,

L = (1 m)(1/2)

L = 0.5 m

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3 years ago

Examine the scenario. Object A has 5 protons and 5 electrons. Object B has 5 protons and 7 electrons. Which option most accurate

Travka [436]

Last choice on the list:
Object A has a net charge of 0 because the positive and negative
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Object B has a net charge of –2 because there is an imbalance of
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3 years ago

During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca

Dmitriy789 [7]

Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

g is the acceleration due to the gravity = 9.81 m/s²

Now,

the centripetal acceleration is given as,

$a=\frac{v^2}{r}$

r is the radius of the loop

on substituting the respective values, we get

$8\times9.81=\frac{340^2}{r}$

r = 1472.98 m

5 0

4 years ago