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Eva8 [605]
3 years ago
6

Can you answer this math homework? Please!

Physics
1 answer:
notka56 [123]3 years ago
5 0

\large \mathfrak{Solution : }

Average speed :

  • \boxed{ \dfrac{distance \:  \: covered}{total \:  \: time \:  \: taken} }

  • \dfrac{100}{8}

  • 12.5 \:  \: m/s

The horizontal (flat) line on a Distance - time graph shows that the body is at rest because the value of Distance (on y - axis ) is same for increasing time ( on x - axis ), it basically shows that the object is at the same position with the change in time.

therefore, correct option is :

  • a. \:  \: the \:  \: object \:  \: is \:  \: not \:  \: moving
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using satellite

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A crane raises a crate with a mass of 150 kg to a height of 20 m. Given that
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Answer:

\boxed {\boxed {\sf 29,400 \ Joules}}

Explanation:

Gravitational potential energy is the energy an object possesses due to its position. It is the product of mass, height, and acceleration due to gravity.

E_P= m \times g \times h

The object has a mass of 150 kilograms and is raised to a height of 20 meters. Since this is on Earth, the acceleration due to gravity is 9.8 meters per square second.

  • m= 150 kg
  • g= 9.8 m/s²
  • h= 20 m

Substitute the values into the formula.

E_p= 150 \ kg \times 9.8 \ m/s^2 \times 20 \ m

Multiply the three numbers and their units together.

E_p=1470 \ kg*m/s^2 \times 20 m

E_p=29400 \ kg*m^2/s^2

Convert the units.

1 kilogram meter square per second squared (1 kg *m²/s²) is equal to 1 Joule (J). Our answer of 29,400 kg*m²/s² is equal to 29,400 Joules.

E_p= 29,400 \ J

The crate has <u>29,400 Joules</u> of potential energy.

7 0
3 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the man

In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

m=\frac{\Delta U}{g\Delta h}=\frac{4620 J}{(9.8 m/s^2)(8.4 m)}=56 kg

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What is the velocity (in m/s) of a 550 kg roller coaster cart at the bottom of the track if it started with 990,000 J of gravita
sesenic [268]

Answer:

60m/s

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g.p.e = k.e

k.e = 0.5 × mass × velocity²

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V² = 3600

V = 60m/s

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