Heya!!
For calculate aceleration, lets applicate second law of Newton:
![\boxed{F=ma}](https://tex.z-dn.net/?f=%5Cboxed%7BF%3Dma%7D)
<u>Δ Being Δ</u>
F = Force = 183 N
m = Mass = 367 kg
a = Aceleration = ?
⇒ Let's replace according the formula and clear "a":
![\boxed{a=183 \ N / 367\ kg}](https://tex.z-dn.net/?f=%5Cboxed%7Ba%3D183%20%5C%20N%20%2F%20367%5C%20kg%7D)
⇒ Resolving
![\boxed{ a = 0.49 \ m/s^{2}}](https://tex.z-dn.net/?f=%5Cboxed%7B%20a%20%3D%200.49%20%5C%20m%2Fs%5E%7B2%7D%7D)
Result:
The aceleration is <u>0,49 meters per second squared (m/s²)</u>
Good Luck!!
Explanation:
For most temperature scales, the boiling point of water and the freezing point is used to calibrate it.
Three known temperature scales;
- Kelvin scale
- Celcius scale
- Fahrenheit scale
Kelvin scale Celcius scale Fahrenheit scale
Freezing point 273K 0°C 32°F
Melting point 373K 100°C 212°F
<u>C</u> is the correct answer, because energy cannot be created neither destroy. The energy is changing from chemical to from electric to light, and from light to heat.
Answer:
Entonces seria 127 para vencer.
Explanation:
espero averte ayudado:-)
The answer is C.
The Kinetic energy which was exerted and experience pulling the string of a bow is kept as a potential energy at the end of the arrow in contact with the string. Once release from aim at stationary position the potential energy is again transformed.