Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
Step-by-step explanation:
Given that;
p = 10% = 0.1
so let q = 1 - p = 1 - 0.1 = 0.9
n = 818
μ = np = 818 × 0.1 = 81.8
α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58
Now to find P( x < 100)
we say;
Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12
P(x<100) = P(z < 2.12)
from z-score table
P(z < 2.12) = 0.9830
Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
Answer: 13
Step-by-step explanation: It goes up by 5 so 8, 13, 18, 23, and etc
Please tell me if I'm wrong
Answer: 22/21
Step-by-step explanation:
2 cakes : 7 donuts → 6 cakes : 21 donuts
3 cakes : 11 brownies → 6 cakes : 22 brownies
22 brownies : 21 donuts
Now, simply write this as a fraction. 22/21
Solve using equations:
Gina 11 = a+b+c
Sam 27 = 2a+3b+2c
Robby 19= a+2b+2c
Gina *2 give 22=2a+2b+2c (subtract this from Sam to give)
b=5
the subtract Robby from Gina *2 to give a=3
[Question 1]
let d = number of dramas Gina rented, c = # of comedies, and t = # of documentaries:
[equation a] d + c + t = 11
[equation b] 2d + 3c + 2t = 27
[equation c] d + 2c + 2t = 19
if we subtract [a] from [c] we get:
[equation d] c + t = 8
if we subtract [c]*2 from [b] we get:
[equation e] -c - 2t = -11 or
[equation e] c + 2t = 11
Now we can subtract [e] from [d] to solve for t:
t = 3
Now put in 3 for t in [d] or [e] to solve for c:
c + 2(3) = 11
c + 6 = 11
c = 5
So she rented 5 comedies and 3 documentaries which leaves 3 dramas (which is answer A)
Answer:
The total length of the border is 
Step-by-step explanation:
we know that
The circumference of a circle is equal to
we have
assume
substitute
