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3 years ago

Evaluate the following: csc(0)= sec(0)= cot(0)=

Mathematics

2 answers:

ololo11 [35]3 years ago

7 0

Answer:

Step-by-step explanation:

we need that theta angle .. soooo.... use SOH CAH TOA to remind yourself how the trig functions fit on the triangle.....

since we have all 3 side any one of the above trig functions would work. as a side note.. Tan is limited to the 1st quadrant on a calculator.. so maybe Cos is a good choice. although it would work in this case....

sooo ....

Cos(Ф) = Adj / Hyp

Ф = arcCos( 24 /25)

Ф ≈16.26°

I don't have csc on my calculator but I know that 1/sin = csc sooo

csc(16.26)=1/sin(16.26) ≈ 3.57

sec(16.26)= 1/cos(26.26) ≈ 1.041

cot(16.26) = cos(16.26) / sin(16.26) ≈3.476

USPshnik [31]3 years ago

6 0

Answer:

csc(0)= 25/7

sec(0)= 25/24

cot(0)= 24/7

Step-by-step explanation:

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A tour operator has a bus that can accommodate 20 tourists. The operator knows that tourists may not show up, so he sells 21 tic

dalvyx [7]

Answer:

The expected revenue of the tour operator is 985.

Step-by-step explanation:

There are two outcomes:

Either less than 21 tourists show up and the operator does not have to pay anything. Or 21 tourists show up and the operator has to repay 100.

Anyways, initially he gets the price of all the tickets sold. That is 21 each at 50, so $R = 21*50 = 1050$ .

Then, we need to find the probability that all of the 21 tourists show up. In this case, we have to subtract 100 from the revenue.

Each tourist has a 0.02 probability of not showing up. This means that each has a 1-0.02 = 0.98 probability of showing up. So the probability P that all 21 tourists show up is $P = (0.98)^{21} = 0.6542$ .

So, the expected revenue of the tour operator is

$R = 1050 - 100P = 1050 - 100(0.6542) = 984.58$

Rounded up, the expected revenue of the tour operator is 985.

6 0

3 years ago

A new school has x day students and y boarding students.

guapka [62]

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as $x + 2y\geq 1200$ .

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are $\$600$ a term.

So, the fees for $x$ day students are $\$600x$ a term.

The fees for a boarding student are $\$1200$ a term.

The fees for $y$ boarding student are $\$1200y$ a term.

Total fees for $x$ day students and $y$ boarding student is:

$\text{Total fees}=600x+1200y$

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

$600x+1200y\geq 720000$

$600(x+2y)\geq 720000$

Divide both sides by 600.

$\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}$

$x+2y\geq 1200$

Hence proved.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=4x%20%2B%203y%20%3D%200%20%5C%5C5y%20%2B%2053%20%3D%2011x%20%5C%5C%20" id="TexFormula1" title=

Anvisha [2.4K]

Answer:

x = 3, y = -4

Step-by-step explanation by substitution:

Solve the following system:

{4 x + 3 y = 0 | (equation 1)

5 y + 53 = 11 x | (equation 2)

Express the system in standard form:

{4 x + 3 y = 0 | (equation 1)

-(11 x) + 5 y = -53 | (equation 2)

Swap equation 1 with equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

4 x + 3 y = 0 | (equation 2)

Add 4/11 × (equation 1) to equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+(53 y)/11 = -212/11 | (equation 2)

Multiply equation 2 by 11/53:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+y = -4 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(11 x)+0 y = -33 | (equation 1)

0 x+y = -4 | (equation 2)

Divide equation 1 by -11:

{x+0 y = 3 | (equation 1)

0 x+y = -4 | (equation 2)

Collect results:

Answer: {x = 3 , y = -4

_____________________________________

Solve the following system:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Isolate terms with x to the left hand side.

Subtract 3 y from both sides:

{4 x = -3 y

5 y + 53 = 11 x

Hint: | Solve for x.

Divide both sides by 4:

{x = -(3 y)/4

5 y + 53 = 11 x

Hint: | Perform a substitution.

Substitute x = -(3 y)/4 into the second equation:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for y:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Isolate y to the left hand side.

Subtract 53 - (33 y)/4 from both sides:

{x = -(3 y)/4

(53 y)/4 = -53

Hint: | Solve for y.

Multiply both sides by 4/53:

{x = -(3 y)/4

y = -4

Hint: | Perform a back substitution.

Substitute y = -4 into the first equation:

Answer: {x = 3 , y = -4

7 0

3 years ago

Giving brainliest!!!!!!!!!!

lisov135 [29]

I think the answer is y=X+10

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3 years ago

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What is length?define

pogonyaev

Step-by-step explanation:

the measurement or extent of something from end to end; the greater of two or the greatest of three dimensions of an object.

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4 years ago

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