Answer:
Explanation:
The following code is written in Java it goes through the queue that was passed as an argument, loops through it and removes all the odd numbers, leaving only the even numbers in the queue. It does not add any more data structures and finally returns the modified queue when its done.
public static Queue<Integer> evens(Queue<Integer> queue) {
int size = queue.size();
for(int x = 1; x < size+1; x++) {
if ((queue.peek() % 2) == 0) {
queue.add(queue.peek());
queue.remove();
} else queue.remove();
}
return queue;
}
Answer:
hmmmmm...hold up let me look up what dark supereffective means XD...
Explanation:
?oh so i only see stuff about pokemon so id imagine its about that...
Answer:
385
Explanation:
There was no question so I simply run the program for you and included the output.
The program seems to calculate: 
Answer:
Given the number of platters =5
A. Hence, the number of recording surface =10
B. number of read-write heads =10
C. Number of arms holding the read-write heads = 10
Explanation:
We know that number of recording surface = 2 *( number of platters)
= 2*5=10
And the number of read-write heads = number of recording surface= 10
Also, number of arms holding the read-write head = one for each read-write head= 10
And hence, the above answer.
Answer:
1 1
2
3
5
8
13
21
34
55
Explanation:
i guess this is the answer