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Marina CMI [18]

3 years ago

6

Is 22/13 equivalent to 13/4?

1 answer:

Amiraneli [1.4K]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

22/13 =1.69≈3.2

13/4 = 3.2

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What is the axis of symmetry for the graph of y-4x=7-x^2

STALIN [3.7K]

It is symmetrical about the y axis

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4 years ago

At a height of about 212 meters, One Shell Square is the tallest building in New Orleans. Marlie is creating a scale model of th

SIZIF [17.4K]

$\bf \begin{array}{ccllll}
building&model\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
250&1\\
212&x
\end{array}\implies \cfrac{250}{212}=\cfrac{1}{x}$

solve for "x"

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4 years ago

A line goes through the points (4,16) Ana (7,19). Write a linear function rule in terms of x and y for this line

Eva8 [605]

Linear function rule in terms of x and y for this line is y = x + 12

<em><u>Solution:</u></em>

Given that a line goes through the points (4, 16) and (7, 19)

To find: linear function rule in terms of x and y for this line

A linear function is a function of the form f(x) = ax + b, where a and b are real numbers. Here, a represents the slope of the line, and b represents the y-axis intercept

<em><u>The slope intercept form is given as:</u></em>

y = mx + c

Where "m" is the slope of line and "c" is the y - intercept

Let us first find slope of line

<em><u>The slope "m" of a line is given as:</u></em>

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text {Here } x_{1}=4 \text { and } x_{2}=7 \text { and } y_{1}=16 \text { and } y_{2}=19$

$m=\frac{19-16}{7-4}=\frac{3}{3}=1$

Thus the slope of line is 1

Substitute m = 1 and (x, y) = (4, 16) in y = mx + c

16 = 1(4) + c

c = 16 - 4 = 12

Substitute c = 12 and m = 1 in slope intercept form

y = 1x + 12

y = x + 12 is the required linear function rule

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4 years ago

❤️❤️making sure I chose the right one❤️

KengaRu [80]

Yes, angle B and angle D are equal, so it is true

6 0

3 years ago

Read 2 more answers

Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-

Charra [1.4K]

Answer:

The statement is true is for any $n\in \mathbb{N}$ .

Step-by-step explanation:

First, we check the identity for $n = 1$ :

$(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}$

$1 = \frac{1\cdot 1\cdot 3}{3}$

$1 = 1$

The statement is true for $n = 1$ .

Then, we have to check that identity is true for $n = k+1$ , under the assumption that $n = k$ is true:

$(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)$

$2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)$

$(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)$

Therefore, the statement is true for any $n\in \mathbb{N}$ .

4 0

3 years ago