Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53 (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a - 3b = 26
------------------- - (substract)
5b = 80
b = 80/5
b = 16
Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
a = 53 - 16
a = 37
The numbers are 16 and 37</span>
Y =Mx + C
where M = gradient / slope
C = y intercept
comparing with y = 2x - 3
M = 2
C = -3
<span>Data
set X and data set Y both have the same interquartile range. If the
first quartile of data set X is less than the first quartile of data set
Y, then the third quartile of data set X is greater than the third
quartile of data set Y.
False</span>
Im not too sure what friendly numbers are being that I never leraned that but
14*25*4 is 1400
work:
the easiest thing to do first is 25*4 which gives you a product of 100
the multiply 14 by 100 wich is 1400
i hope this helped
