Answer:

Explanation:
Hello there!
in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:

Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:

Thus, the mass percentage is calculated as shown below:

Regards!
Where is the other statements
Mass/moles x mr
so you need to work out the rfm of Ca(OH)2= 40(16+1)2= 40+34= 74
and then use the formula= moles x mr
6.25 x 74= 462.5
Answer= 462.5g