
Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
The blank spaces about the passage can be filled with the following correct vocabulary respectively.
- inequality
- strict inequality
- compound inequality
- solution sets
- true
<h3>Inequality</h3>
An <u>inequality</u> is a relation between two numbers and/or expressions that are related via <, >, ≥ or ≤ sign.
A <u>strict inequality</u> is an expression that uses < and >. It tells us that one side is only more or less than the other side.
When 2 simple inequalities are joined by or and, we get a <u>compound inequality</u>.
When solving an inequality, the solution will be a range of values called its <u>solution sets</u>. The inequality will remain <u>true</u> for every single value in this range.
The inequality signs are;
- Greater than >
- Less than <
- Greater than or equal to ≥
- Less than or equal to ≤
- Equal to =
Learn more about inequality:
brainly.com/question/25275758
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Multiplicand is the number that gets multiplied, multiplier is the number that you are multiplying by, product is the result of mulptiplication multiplicand by multiplier.
Let a be a multiplicand, b be a multiplier and c be a product, then
a·b=c.
To check the correctness of the answer to a multiplication example, you should divide the product c by the multiplier b:
c÷b=a.
Answer: correct choice is A.
No solution for the quadratic equation because of the √-20
They have different masses