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antoniya [11.8K]

3 years ago

5

At a pep rally 14 out of 20 students who entered the gym were carrying a backpack. Based on this information, if 1,400 students

were at the pep rally, how many students could be expected to be carrying a backpack

2 answers:

kondaur [170]3 years ago

4 0

Answer:

980 students

Step-by-step explanation:

14/20=x/1400

cross multiplication and then u get the equatiton 20x=19600

solve and get 980

Nadya [2.5K]3 years ago

3 0

Answer:

980 students

Step-by-step explanation:

14/20=x/1400

20x=19600

x=980

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KonstantinChe [14]

Answer:

All in the explanation.

Step-by-step explanation:

Since we will only be renting the car for one day it will only be a $50 dollar base fee. If we drive 192 miles and just rent it for one day the equation modeled will be $0.18(192) + 50 = 34.56 + 50 = $84.56 total.

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3 years ago

Together, Rhonda and Margo saved $478.50. If Rhonda saved $225 of that total, how much did Margo save? Select the addition equat

Sav [38]

Answer:

$253.5

Step-by-step explanation:

Total amount saved = Amount Rhonda saved + Amount Margo saved

= $478.50 − $225

Amount Margo saved = $253.5

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3 years ago

The brand manager for a brand toothpaste must plan a campaign designed to increase brand recognition. He wants to first determin

bulgar [2K]

We need to find out how many adults must the brand manager survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage.

From the given data we know that our confidence level is 90%. From Standard Normal Table we know that the critical level at 90% confidence level is 1.645. In other words, $Z_{Critical}=1.645$ .

We also know that E=5% or E=0.05

Also, since, $\hat{p}$ is not given, we will assume that $\hat{p}$ =0.5. This is because, the formula that we use will have $\hat{p}(1-\hat{p})$ in the expression and that will be maximum only when $\hat{p}$ =0.5. (For any other value of $\hat{p}$ , we will get a value less than 0.25. For example if, $\hat{p}$ is 0.4, then $1-\hat{p}=0.6$ and thus, $\hat{p}(1-\hat{p})=0.24$ .).

We will now use the formula

$n=(\frac{Z_{Critical}}{E})^2\hat{p}(1-\hat{p})$

We will now substitute all the data that we have and we will get

$n=(\frac{1.645}{0.05})^2\times0.5(1-0.5)$

$n=(32.9)^2\times0.25$

$n=270.6025$

which can approximated to n=271.

So, the brand manager needs a sample size of 271

3 0

3 years ago

Match the situation to the most appropriate graph #7

tatuchka [14]

Graph K. This is because the cost of a gallon of milk is not increasing constantly, as in a linear rate, but it has only increased a few times in a year. Therefore, graph K shows that a gallon of milk is a steady, unchanged price, then the cost rises and stays the same, then rises again and stays the same. So, it is not a linear graph because the cost of the milk is not going up at a constant rate.

4 0

3 years ago

A car travels at constant speed for 7 days and covers 1500 miles. What is the speed in centimeters/minute? You may use the (appr

zvonat [6]

Answer:

Speed = 23809.52 cm/min

Step-by-step explanation:

Given : A car travels at constant speed for 7 days and covers 1500 miles.

To find : What is the speed in centimeters/minute

Solution : Formula to find speed is

$\text{Speed}=\frac{\text{Distance}}{\text{Time}}$

Distance traveled = 1500 miles and time taken = 7 days

$\text{Speed}=\frac{\text{1500 miles}}{\text{7 days}}$

Now, we have to convert miles into centimeter and days into minutes.

1 day = 24 hours

1 hour= 60 minute

24 hr= 24×60 minute

1 day = 24×60 minute

7 days = 7×24×60 minute = 10,080 minute

Now, 1 mile = 8/5 km = 1.6 km

1 km= 100000 cm

1.6 km = 1.6 × 100000 cm

1 mile = 1.6 × 100000 cm

1500 miles = 1500×1.6 × 100000 cm = 240,000,000 cm

Put back the values into speed

$\text{Speed}=\frac{\text{1500 miles}}{\text{7 days}}$

$\text{Speed}=\frac{\text{240,000,000 cm}}{\text{10,080 minute}}$

$\text{Speed}=\text{23809.523 cm/minute}$

Therefore, speed = 23809.52 cm/min

3 0

3 years ago

Read 2 more answers