Suppose the commute times for employees of a large company follow a
2 answers:
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Answer:
C) (-3, -1)
Step-by-step explanation:
y = 5/3x + 4
When x = 0, y = 4
When y = 0, x = -2.4
graph the points: (0, 4) and (-2.4, 0)
y = -2/3x - 3
When x = 0, y = -3
When y = 0, x = -4.5
graph the points: (0, -3) and (-4.5, 0)
The lines will cross at point: (-3, -1)
Third leg.
The crew flies at a speed of 560 mi/h in direction N-20°-E.
The wind has a speed of 35 mi/h and a direction S-10°-E.
We then can draw this as:
We have to add the two vectors to find the actual speed and direction.
We will start by adding the x-coordinate (W-E axis):
and the y-coordinate (S-N axis) is:
Then, the actual speed vector is v3=(197.61, 491.76).
The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].
Then, we have to calculate the displacement in 20 minutes using the actual speed vector.
We can calculate the movement in each of the axis. For the x-axis:
NOTE: 20 minutes represents 1/3 of an hour.
We can do the same with the y-coordinate:
The final position is R3 = (282.53, 331.59).
To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:
The distance can be calculated as if it was a right triangle:
The angle, from E to N, can be calculated as:
If we want to express it from N to E, we substract the angle from 90°:
Answer: the final location can be represented with the vector (282.53, 331.59).
1) The distance from the origin is 435.63 miles and
2) the direction is N-40°-E.
