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1 year ago

I have 28 students in my MAT121 class who recently took a test. Their results are graphed below.

Mathematics

1 answer:

bekas [8.4K]1 year ago

5 0

Considering the box-and-whisker plot, it is found that:

a) 25% of the students scored less than 60.

b) 25% of the students received a score greater than 85.

<h3>What does a box-and-whisker plot shows?</h3>

A box and whisker plot shows three things:

The 25th percentile, which is the median of the bottom 50%.

The median.

The 75th percentile, which is the median of the upper 50%.

From the plot given in the graph, we have that:

The 25th percentile is of 60, hence 25% of the students scored less than 60.

The 75th percentile is of 85, hence 25% of the students received a score greater than 85.

More can be learned about a box-and-whisker plot at brainly.com/question/27608957

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The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the length,

Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: $(2w+33)^2=w^2+(2w+31)^2$ . Distributing by multiplying we simplify to $4w^2+132w+1089=w^2+4w^2+124w+961$ . We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have $w^2-8w-128=0$ . The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

8 0

3 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

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2 years ago

For the function y = 9x, what is the output value if 5 is the input value?

Vinil7 [7]

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2 years ago

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bezimeni [28]

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3 years ago

which equation can replace 3x 5y = 59 in the original system and still produce the same solution? 2x – y = –4 10x – 5y = –20 7x

natka813 [3]

From my research, the original system of equations contain the following equations:

<span>2x − y = −4
3x + 5y = 59

where obtained solution is x = 3

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3 years ago

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