The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)
<h3>The nth term of a geometric sequence</h3>
First term, a1 = -6
Fifth term, a5 = -486
a5 = ar^(n - 1)
-486 = -6 × r^(5-1)
-486 = -6r⁴
r⁴ = -486 / 6
r⁴ = 81
r = 4√81
r = 3
Geometric rule:
nth term = ar^(n-1)
nth term = -6 × 3^(n - 1)
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This is what I get not sure if the problem on numerator is together if it is then . X^2+(a^2+1) x^2+a^2+1.
-----------------= ----------------- AX+1. Ax+1 Answer: a^2+x^2+1 ---------------- AX+1
If I wrote the actual problem wrong let me know. This is what I understood.
<h3>Answer:</h3>
One line segment is 10 cm and the other one is 45 cm
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It's 82 degrees. Subtract your minor arc (98) by 360 to get your major arc, which is 262. Then, subtract 98 (minor arc) from 262 (major arc), which gives you 164. Finally, divide 164 by 2 to get angle ABC.