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nataly862011 [7]
3 years ago
10

Evaluate the expression. | -12 | - |8|

Mathematics
2 answers:
Kay [80]3 years ago
8 0

Answer:

=/-12/-/8/ [modulus od negative 12 is positive 12 ] and 8 is 8

=12-8

=4

LenaWriter [7]3 years ago
3 0

Answer:

it is 12 - 8

Step-by-step explanation:

The absolute value of -12 is 12. The absolue value of 8 is 8.

12 - 8 = 4.

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7(9) = 9(7)
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Answer:

A) Commutative

Step-by-step explanation:

The Associative has to do with re-grouping numbers. There are only two numbers so this does not apply here. Commutative is where you change the order; that's what the equation is demonstrating.

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What is the solution to the inequality 5.25 -b >6.5?
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d = 53

\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \lim_{n \to \infty} a_n

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Calculate the cost of 8 cans if 2 cans of olive oil cost 24
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96

Step-by-step explanation:

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During basketball practice, Grant made 8 out of 10 free throws. If he attempts 50 free throws, how many times is he likely to mi
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The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
3 years ago
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