Incomplete question as the car's speed is missing.I have assumed car's speed as 6.0m/s.The complete question is here
An amusement park ride consists of a car moving in a vertical circle on the end of a rigid boom of negligible mass. The combined weight of the car and riders is 6.00 kN, and the radius of the circle is 15.0 m. At the top of the circle, (a) what is the force FB on the car from the boom (using the minus sign for downward direction) if the car's speed is v 6.0m/s
Answer:
Explanation:
Set up force equation
∑F=ma
∑F=W+FB
The minus sign for downward direction
B,
The 25 N and 5 N force are acting in the same direction so we can add them together, but the 10 N force acts in the opposite direction so you subtract it.
25 N + 5 N - 10 N = 20 N
The forms of kinetic energy are motion, heat, sound and light.
So according to your options, I choose D) Sound energy.
Each point along the track of one solar mass star represents the star's surface temperature and luminosity at one time.
<h3>What is the one-solar mass star?</h3>
A star having a mass equal to the mass of the Sun is called a one-solar mass star.
Its life track shows the luminous intensity as well as the surface temperature.
Learn more about one-solar mass star.
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C, planets orbit around the sun because of gravity
