Explanation:
Given that,
Initial speed of the bag, u = 7.3 m/s
Height above ground, s = 24 m
We need to find the speed of the bag just before it reaches the ground. It can be calculated using third equation of motion as :
v = 22.88 m/s
So, the speed of the bag just before it reaches the ground is 22.38 m/s. Hence, this is the required solution.
Answer:
I would say the answer is A... but I'm not so sure ....
Answer:
16 ohms
Explanation:
V=
I
⋅
R
where, V is the net potential difference in the circuit, I is the current in the circuit and R is the net resistance of the circuit.
In this case, V
=
240 volts, I
=
15 amperes.
240
=
15
⋅
R
⇒
R
=
240/
15
=
16 ohms
Answer: The density of this piece of jewelry is 
Explanation:
To calculate the density, we use the equation:
Mass of piece of jewellery = 130.8 g
Density of piece of jewellery = ?
Volume of piece of jewellery =( 62.4-47.7 ) ml = 14.7 ml = 
Putting values in above equation, we get:
Thus density of this piece of jewelry is
