Answer:
d. 2m to the right of the pivot
Explanation:
m1 = m
m2 = 0.5m
d1 = 1m
d2 = ?
from principle of moment,
CWM = ACWM
m × 1 = 0.5m × d2
d2 = m/0.5m
= 1/0.5
= 2m
The 2nd child will have to sit 2m to the right
The turning effect of a force is known as the moment. It is the product of the force multiplied by the perpendicular distance from the line of action of the force to the pivot or point where the object will turn.
The principle of moments states that when in
equilibrium the total sum of the anti clockwise
moment is equal to the total sum of the
clockwise moment.
When a system is stable or balance it is said to be in equilibrium as all the forces acting on the system cancel each other out.
In equilibrium
Total Anticlockwise Moment = Total
Total Anticlockwise Moment = TotalClockwise Moment
Answer:
Explanation:
20 km/hr = 5.56 m/s
90 km/hr = 25 m/s
To have just passed C, B must gain first the length of C, then the length of B for a total 400 m
s = s₀ + v₀t + ½at²
if s₀ = 0 at the head of train C when t = 0
for train C, the position in time is
s = 0 + 5.56t + ½(0.2)t²
s = 5.56t + 0.1t²
for train B which must gain 400 m in the same time
s = -400 + 25t + ½(-0.1)t²
s = -400 + 25t - 0.05t²
As both equations equal s, we can set the other sides equal
5.56t + 0.1t² = -400 + 25t - 0.05t²
0.15t² - 19.44t + 400 = 0
quadratic formula positive answer
t = (19.44 + √(19.44² - 4(0.15)(400))) / (2(0.15))
t = 104 s
v = 25 + 104(-0.1) = 14.6 m/s or 52.6 km/hr
Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
Hope this Helps!!!
Answer:
itsgoing to be aroud 36 speed
Explanation:
bc if u think about it it make sence
260 meters im pretty sure because rate*time=distance