PART a)
here when stone is dropped there is only gravitational force on it
so its acceleration is only due to gravity
so we will have

Part b)
Now from kinematics equation we will have

now we have
y = 25 m
so from above equation


Part c)
If we throw the rock horizontally by speed 20 m/s
then in this case there is no change in the vertical velocity
so it will take same time to reach the water surface as it took initially
So t = 2.26 s
Part D)
Initial speed = 20 m/s
angle of projection = 65 degree
now we have




PART E)
when stone will reach to maximum height then we know that its final speed in y direction becomes zero
so here we can use kinematics in Y direction



so it will take 1.85 s to reach the top
I can't think of any way that pressure can be decreased due to added pressure.
Be that as it may, and it certainly still is ...
No matter what you do to the pressure or the temperature of
the gas in that tank, the volume doesn't change. Any sample
of gas always expands to fill the container in which it's confined.
Its volume doesn't change until you either transfer it to another
container with different volume, or else change the volume of
the container it's in.
Answer:
98N and 147N
Explanation:
We have the following information:

We can find the static fricton force as follow,

Where N is the normal force (mg)

Static friction force at 147N is greater than the force applied hence body does not move.

I think 30 as that’s usually average speed
Since it is restricted at both ends, λ/2 = length of string
λ/2 = 1.5m
λ = 1.5*2 = 3m