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Margaret [11]
2 years ago
9

Is a neutron positive ornegative

Physics
2 answers:
DIA [1.3K]2 years ago
6 0

Answer:

neither

Explanation:

Neutrons have no charge and have their name because of their "neutral" charge. Protons are positively charged and electrons are negatively charged.

AleksandrR [38]2 years ago
5 0
Neutrons are neutral which means they have no charge.
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Since many wavelengths of light are measured in nanometers, it's useful to know that planck's constant (h) multiplied with the s
MrRa [10]

Answer:

E = h f      and since f = c / λ     we have E = h c / λ

Thus  λ = h c / E

Also, 1 ev = 1.6E-19 C

λ = 6.63E-34 * 3.0E8 / (1.6 * 1.6E-19)

λ = 6.63 * 3.0 / (1.6 * 1.6) * E-7

λ = 7.77E-7 = 777 nanometers

(B) is correct

4 0
2 years ago
Henry shot a down tennis ball and a cricket ball of the same size to window glass. Which one will have more impact? Justify.​
babunello [35]

Answer: The cricket ball bc of the material

Explanation:

5 0
2 years ago
Which rational number could be graphed between 0 and 1?A number line going from negative 5 to positive 3 in increments of 1.Nega
vovikov84 [41]

In order to find which rational number is between 0 and 1, let's convert them into their decimal form:

\begin{gathered} \text{negative one-half:} \\ -\frac{1}{2}=-0.5 \\  \\ \text{one}-\text{fourth:} \\ \frac{1}{4}=0.25 \\  \\ \text{three}-\text{halves:} \\ 3\cdot\frac{1}{2}=\frac{3}{2}=1.5 \\  \\ 1.75 \end{gathered}

Looking at the numbers in their decimal form, we can see that the number between 0 and 1 is one-fourth, therefore the correct option is the second one.

7 0
1 year ago
A ball is hit with a paddle, causing it to travel straight upward. It takes 2.90 s for the ball to reach its maximum height afte
zmey [24]

Answer:

A. 28.42 m/s

B. 41.21 m

Explanation:

From the question given above, the following data were obtained:

Time (t) to reach the maximum height = 2.90 s

Initial velocity (u) =?

Maximum height (h) =?

A. Determination of the initial velocity of the ball.

Time (t) to reach the maximum height = 2.90 s

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =?

v = u – gt (since the ball is going against gravity)

0 = u – (9.8 × 2.9)

0 = u – 28.42

Collect like terms

0 + 28.42 = u

u = 28.42 m/s

Thus, the initial velocity of the ball is 28.42 m/s

B. Determination of the maximum height reached by the ball.

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) = 28.42 m/s

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 28.42² – (2 × 9.8 × h)

0 = 807.6964 – 19.6h

Collect like terms

0 – 807.6964 = – 19.6h

– 807.6964 = – 19.6h

Divide both side by – 19.6

h = – 807.6964 / – 19.6

h = 41.21 m

Thus, the maximum height reached by the ball is 41.21 m

5 0
3 years ago
If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 70 km/h . The c
olganol [36]

as it is given that curved marked the speed as v = 70 km/h

so we will first convert the speed into m/s

v = 70 km/h = 19.44 m/s

now we know that here friction force will provide centripetal force

F_c = F_f

As we know that centripetal force is given as

F_c = \frac{mv^2}{R}

\frac{mv^2}{R} = \mu_k mg

\frac{v^2}{R} = \mu_k g

v^2 = \mu_k R * g

19.44^2 = 0.5* R * 9.8

378 = 4.9 * R

R = 77.1 m

3 0
4 years ago
Read 2 more answers
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