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Viktor [21]
3 years ago
6

Flagpole to the ground using a piece of rope that is 10 feet long. He is going to tie the rope to the top of the flagpole and th

en secure the other end of the rope to the ground. The flagpole is 8 feet high. How far out on the ground does he need to secure the rope from the flagpole so that the rope is tight?
Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

<h3>6 feet</h3>

Step-by-step explanation

Using the pythagoras theorem;

Given

The length of the flag pole = 8 feet = opposite side

Length of the rope = 10 feet = hypotenuse

To determine how far out on the ground he need to secure the rope from the flagpole so that the rope is tight, we need to look for the adjacent. Using the equation

hyp² = opp² + adj²

10² = 8² + adj²

adj² = 100-64

adj² = 36

adj = √36

adj = 6feet

Hence the rope should be placed 6feet out of the ground

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Answer:

1. -5x+3y+44=0

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If a line passing through two points then the equation of line is

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1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

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We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

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