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ziro4ka [17]
2 years ago
12

Go step by step to reduce the radical. The square root of 96

Mathematics
1 answer:
lakkis [162]2 years ago
5 0

Answer:

Step-by-step explanation:

We want to reduce the radical. In order to do that, we want to find the factors of 96 that are square numbers

The factors of 96 are:

1, 96, 2, 48, 3, 32, 4, 24, 6, 16...

16 is a square number, so we can rewrite

\sqrt{96} = \sqrt{16*6}  = \sqrt{16} * \sqrt{6}  = 4\sqrt{6}

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What is the value of x? <br> -2/7x+6+1/7x=18 <br> x=
Alenkinab [10]
- \frac{2}{7} x + 6 + \frac{1}{7} x = 18

First, simplify \frac{2}{7} x to \frac{2x}{7} / Your problem should look like: -\frac{2x}{7} + 6 + \frac{1}{7} x = 18
Second, simplify \frac{1}{7} x to \frac{x}{7} / Your problem should look like: - \frac{2x}{7} + 6 + \frac{x}{7} = 18
Third, simplify - \frac{2x}{7} + 6 + \frac{x}{7} to - \frac{x}{7} + 6 / Your problem should look like: -\frac{x}{7} + 6 = 18
Fourth, regroup terms. / Your problem should look like: 6 - \frac{x}{7} = 18
Fifth, multiply both sides by 7. / Your problem should look like: 42 - x = 126
Sixth, subtract 42 from both sides. / Your problem should look like: -x = 126 - 42
Seventh, simplify 126 - 42 to 84. / Your problem should look like: -x = 84
Eighth, multiply both sides by -1. / Your problem should look like: x = -84

Answer: x = -84

4 0
3 years ago
-4(4x-4) + 2x - 4 = -30
s344n2d4d5 [400]

Answer:

x=3

Step-by-step explanation:

-4(4x-4)+2x-4+4=-30+4

-4(4x-4)+2x=-26

-14x+16=-26

-14x+16-16=-26-16

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-14x/-14=-42/-14

x=3

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3 years ago
20x+32y=0 <br> -50x-80y=0
german

Answer:

dont know what you need

Step-by-step explanation:

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Find the H.C.F of x² - 3x ,x² - 9​
krek1111 [17]
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7 0
3 years ago
Read 2 more answers
A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

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oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
3 years ago
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