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Alisiya [41]
3 years ago
14

Write an equation of the line passing through point P(2, 3) that is perpendicular to the line y -4 = -2(x+3)

Mathematics
1 answer:
Mariulka [41]3 years ago
3 0
Perpendicular = opposite sign and reciprocal slope
Slope of -2 turns into 1/2
Y-y1 = m(x-x1)
Solution; y-3 = 1/2(x-2)
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(a) \frac{-1i}{2}-1[/tex]

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Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

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After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

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the coordinates of the original points of the vertices of Q map to the corresponding points on the image Q'



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adoni [48]

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Step-by-step explanation: ap ex

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