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fenix001 [56]
3 years ago
8

Can you please help?

Mathematics
2 answers:
sashaice [31]3 years ago
7 0
I’m sorry if it’s wrong but it’s
tigry1 [53]3 years ago
5 0

Step-by-step explanation:

f/p = p(1+i)^n

p= 2500

i=0.03 =3%

n=4

2500(1 + 0.03)^4

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Giovanni has been hired by a local clothing accessory store to make decorative belts that have green and blue beads carefully gl
Len [333]

The system of inequalities that model the number and types green (g)

and blue (b) beads in a belt are as follows;

  • <u>70 < g + b < 74</u>
  • <u>10 < g < 14</u>
  • <u>56 < b < 63</u>
  • \underline{\dfrac{1}{4} \leq \dfrac{b}{g} \leq \dfrac{1}{6}}

<h3>How can s system of inequalities be written?</h3>

The waist size for the belt = ±28 inches

The <em>x</em> represent the number of beads on each belt, we have;

Number of beads per belt 70 < x < 74

Minimum ratio of blue to green beads = 1 : 4

Maximum ratio of blue to green beads = 1 : 6

Therefore;

Minimum number of blue beads = \frac{70}{1 + 6} = 10

Maximum number of blue beads = \frac{74}{1 + 4} ≈ 14

The number of blue beads, <em>b</em>, in a belt is therefore;

  • <u>10 < g < 14</u>

<u />

Minimum number of green beads = \frac{4}{1 + 4} × 70 = 56

Maximum number of green beads = \frac{6}{1 + 6} × 74 ≈ 63

The number of green beads, <em>g</em>, in a belt is therefore;

  • <u>56 < b < 63</u>

The sum of the beads on each belt = g + b = x

Therefore;

<u />

  • <u>70 < g + b < 74</u>

From the given maximum and minimum ratios, we have;

  • \underline{\dfrac{1}{4} \leq \dfrac{b}{g} \leq \dfrac{1}{6}}

Learn more about inequalities here:

brainly.com/question/371134

6 0
2 years ago
GIVING BRAINLIEST! DUE TODAY!!!
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Answer:

0, 4, 7, 9, 11 those r the answers in order

6 0
3 years ago
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Are Simple statements are often just called statements
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Yes they are because if I made a small statement like oh I like your shirt it's still called a statement.
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tamaranim1 [39]

Answer:

  • The function is injective but nor surjective

Step-by-step explanation:

<u>We see that:</u>

  • f(x) = x³

<u>For any x₁ and x₂ ∈ N, </u>

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It it confirmed one-to-one, hence it is injective

<u>Check the surjectivity:</u>

f(x) = y ∈ N

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