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Ivan
2 years ago
6

Consider a turnbuckle that has been tightened until the tension in wire AD is 350 N. Draw the FBD that is required to determine

the internal forces at point J. (You must provide an answer before moving on to the next part.) The FBD that is required to determine the internal forces at point J is
Physics
1 answer:
Mars2501 [29]2 years ago
6 0

Answer:

yes

Explanation:

yes

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As the concentration of a solute in a solution increases, the freezing point of the solution ________ and the vapor pressure of
kykrilka [37]

Answer:

As the concentration of a solute in a solution increases, the freezing point of the solution <u><em>decrease </em></u>and the vapor pressure of the solution <em><u>decrease </u></em>.

Explanation:

Depression in freezing point :

\Delta T_f=K_f\times m

where,

\Delta T_f =depression in freezing point =  

K_f = freezing point constant  

m = molality  ( moles per kg of solvent) of the solution

As we can see that from the formula that higher the molality of the solution is directly proportionate to the depression in freezing point which means that:

  1. If molality of the solution in high the depression in freezing point of the solution will be more.
  2. If molality of the solution in low the depression in freezing point of teh solution will be lower .

Relative lowering in vapor pressure of the solution is given by :

\frac{p_o-p_s}{p_o}=\chi_{solute}

p_o = Vapor pressure of pure solvent

p_s  = Vapor pressure of solution

\chi_{solute} = Mole fraction of solute

p_s\propto \frac{1}{\chi_{solute}}

Vapor pressure of the solution is inversely proportional to the mole fraction of solute.

  1. Higher the concentration of solute more will the be solute's mole fraction and decrease in vapor pressure of the solution will be observed.
  2. lower the concentration of solute more will the be solute's mole fraction and increase in vapor pressure of the solution will be observed.
8 0
2 years ago
1. A perspex box has a 10 cm square base and contains water to a height of 10 cm. A piece of rock of mass 600g is lowered into t
AnnZ [28]

Answer:

(a) The volume of water is 100 cm³

(b) The volume of the rock is 20 cm³

(c) The density of the rock is 30 g/cm³

Explanation:

The given parameters of the perspex box are;

The area of the base of the box, A = 10 cm²

The initial level of water in the box, h₁ = 10 cm

The mass of the rock placed in the box, m = 600 g

The final level of water in the box, h₂ = 12 cm

(a) The volume of water in the box, 'V', is given as follows;

V = A × h₁

∴ The volume of water in the box, V = 10 cm² × 10 cm = 100 cm³

The volume of water in the box, V = 100 cm³

(b) When the rock is placed in the box the total volume, V_T, is given by the sum of the rock, V_r, and the  water, V, is given as follows;

V_T = V_r + V

V_T = A × h₂

∴ V_T = 10 cm² × 12 cm = 120 cm³

The total volume, V_T = 120 cm³

The volume of the rock, V_r = V_T - V

∴ V_r = 120 cm³ - 100 cm³ = 20 cm³

The volume of the rock, V_r = 20 cm³

(c) The density of the rock, ρ = (Mass of the rock, m)/(The volume of the rock)

∴ The density of the rock, ρ = 600 g/(20 cm³) = 30 g/cm³

8 0
3 years ago
An observer that moves with an electrical charge senses:
Shtirlitz [24]

Here observer is moving along with an electrical charge

now magnetic field on a moving charge is given by equation

F = qvB sin\theta

electrical force on a moving charge is given by formula

F = qE

so here we can say when observer is moving with the charge it will have two forces on it

1. magnetic force due to existing magnetic field

2. electric force due to electric field

so here he must have to experience both type of field presence

So here correct answer must be

<em>C- electric and magnetic fields </em>

3 0
3 years ago
Read 2 more answers
If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for f
Free_Kalibri [48]

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

k = 500N/m --- spring constant

x = 0.5m --- stretch

Required

The amount of energy

This is calculated as:

U = \frac{1}{2} kx^2

U = \frac{1}{2} * 500N/m * (0.5m)^2

U = 250N/m * (0.5m)^2

U = 62.5\ J

7 0
2 years ago
Calculate the linear momentum (in kg · m/s) of a pickup truck that has a mass of 1035 kg and is travelling eastward at 31.0 m/s.
Musya8 [376]

Answer:

32085 kg.m/s is the correct answer..

8 0
3 years ago
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