The height of the ball when lifted is given by 7sin(25)=2.96
the gravitational energy is mgh, the kinetic is (1/2)mv². We can set these equal since the pendulum doesn't lose much energy
mgh = (1/2)mv²
we can divide by m (since we don't have it anyways)
gh = v²/2
v=√(gh/2) = √(9.81*2.96/2)=3.8m/s.
Not exactly one of your choices, but the right one none the less
<h3><u>Answer;</u></h3>
<em>-Rubidium (Rb)</em>
<h3><u>Explanation;</u></h3>
- <em><u>Alkali metals are group 1 elements, </u></em>they have a valency of 1 and react by loosing electrons to attain a stable configuration.
- <em><u>The reactivity of alkali metals increases down the group, this is due to the increase in the number of energy levels</u></em> which makes it easier for the valence electrons to be lost.
- Therefore, in our case,<em><u> rubidium will be the most reactive as it contains more number of energy levels</u></em>, therefore it will loose valence electron more easily compared to the other alkali metals above it in the group.
Answer:
The wavelength of the wave is 1.419 cm.
Explanation:
wavelength emitted by the one micro wave = 1.41 cm
beat frequency = 170 M Hz
Let the frequency of the wave is f.
![f=\frac{c}{\lambda }\\\\f =\frac{3\times 10^8}{0.0141}\\\\f = 2.13\times 10^{10} Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bc%7D%7B%5Clambda%20%7D%5C%5C%5C%5Cf%20%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B0.0141%7D%5C%5C%5C%5Cf%20%3D%202.13%5Ctimes%2010%5E%7B10%7D%20Hz)
Let the frequency of the other wave is f'.
![f' = 2.13\times 10^{10}-170\times10^6\\\\f' = 21130\times 10^6 Hz](https://tex.z-dn.net/?f=f%27%20%3D%202.13%5Ctimes%2010%5E%7B10%7D-170%5Ctimes10%5E6%5C%5C%5C%5Cf%27%20%3D%2021130%5Ctimes%2010%5E6%20Hz)
The wavelength is given by
![f' = 21130\times 10^6 Hz\\\lambda = \frac{3\times 10^8}{21130\times 10^6}\\\\\lambda = 0.01419 m = 1.419 cm](https://tex.z-dn.net/?f=f%27%20%3D%2021130%5Ctimes%2010%5E6%20Hz%5C%5C%5Clambda%20%3D%20%20%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B21130%5Ctimes%2010%5E6%7D%5C%5C%5C%5C%5Clambda%20%3D%200.01419%20m%20%3D%201.419%20cm)
Answer:
20.35m per minute
Or
1,221.43 per hour
100/5=20
200/7= 28.57
50/4= 12.5
20+28.57+12.5= 61.07
61.07/3= 20.35m per minute
Or
20.35 x 60= 1,221.43m per hour
Total displacement along the length of mountain is given as
L = 235 m
angle of mountain with horizontal = 35 degree
now we will have horizontal displacement as
x = L cos35
x = 235 cos35 = 192.5 m
similarly for vertical displacement we can say
y = L sin35
y = 235 sin35 = 134.8 m