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DENIUS [597]
2 years ago
11

a race car driver achieved a speed of 53m/s in 14 seconds after taking off from rest from the starting line. what was the averag

e acceleration during this time
Physics
2 answers:
lesya [120]2 years ago
5 0

Answer:

initial velocity= 0

time = 14 sec

final velocity= 53 m/s

a= v-u/t

= 53-0/14

= 3.78 m/s²

I hope it's correct

Veronika [31]2 years ago
3 0

Answer:

53/14

Explanation:

average acceleration = (Vfinal -Vintial)/ time taken

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3 years ago
A worker pushed a 33 kg block 6.1 m along a level floor at constant speed with a force directed 23° below the horizontal. if the
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W = F(h) * d

Where F(h) is the force applied in that direction (horizontal) and d is the distance in that direction. In this case, F(h) is the horizontal component of the applied force, F(app). However, the question doesn't give us F(app), so we need to find it some other way.

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F(h) = F(app)cos(23)

Friction is a little trickier - since the block is being PUSHED into the ground a bit by the vertical component of the applied force, F(v), the normal force, N, is actually a bit more than mg:

N = mg + F(v) = mg + F(app)sin(23)

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F(h) = f
F(h) = uN
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Now that we have F(app), we can find the exact value of F(h):

F(h) = F(app)cos(23)
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And now that we have F(h), we can find W:
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hpoe this helps you.

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