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DENIUS [597]
2 years ago
11

a race car driver achieved a speed of 53m/s in 14 seconds after taking off from rest from the starting line. what was the averag

e acceleration during this time
Physics
2 answers:
lesya [120]2 years ago
5 0

Answer:

initial velocity= 0

time = 14 sec

final velocity= 53 m/s

a= v-u/t

= 53-0/14

= 3.78 m/s²

I hope it's correct

Veronika [31]2 years ago
3 0

Answer:

53/14

Explanation:

average acceleration = (Vfinal -Vintial)/ time taken

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(1 point) A projectile is fired from ground level with an initial speed of 600 m/sec and an angle of elevation of 30 degrees. Us
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Answer:

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R = \frac{u^2sin \ 2\theta}{g} \\\\R = \frac{600^2 sin(2\times 30^0)}{9.8} \\\\R = \frac{600^2 sin (60^0)}{9.8} \\\\R = 31,813.18 \ m

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