1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara31 [8.8K]
3 years ago
13

What is the avarage velocity of a car that travels 30 kilometers due west in 0.5 hours

Physics
2 answers:
Fed [463]3 years ago
6 0
Velocity is distance over time v= \frac{d}{t}. If it wants it in km/h you're good to go otherwise if its m/s you need to convert km to m by multiplying 30 by 1000 and t in hours to seconds by multiplying 0.5 by 3600.
Nikolay [14]3 years ago
5 0
Average velocity=distance/time
average v=s/t
averagev=0.3/30 min
 
so use your calculator 30min into seconds(30/60)
and divide your kilometre with your time(v=distance/time
You might be interested in
Where was land-dwelling found?
Sav [38]
Remote Scottish island
4 0
3 years ago
Read 2 more answers
A narrow region between two air masses of different densities is a
Sav [38]
A front is a narrow region  between two air masses of different densities.
5 0
3 years ago
A metal ion (X) with a charge of 4+ is attracted to a nonmetal ion (Z) with a
Keith_Richards [23]

Answer:

A) X3Z4

Explanation:

8 0
2 years ago
I need help on all of this
wel

dude is -2m/s, ...ettte is +2m/s

pos vel is when dudette, eg, is going in increasing x, in this case.

neg vel  is when dudette, eg, is going in decreasing x, in this case. ie she turns round and runs

zero vel is zero speed. dudette standing still

positive vel neg pos top dia

no

yes

yes

yes

yes

yes

all yes looks like ...




4 0
3 years ago
Calculate the mass (in SI units) of (a) a 160 lb human being; (b) a 1.9 lb cockatoo. Calculate the weight (in English units) of
kondaur [170]

Explanation:

1. Force applied on an object is given by :

F = W = mg

(a) A 160 lb human being, F = 160 lb

g = acceleration due to gravity, g = 32 ft/s²

m=\dfrac{F}{g}

m=\dfrac{160\ lb}{32\ ft/s^2}

m = 5 kg

(b) A 1.9 lb cockatoo, F = 1.9 lb

m=\dfrac{F}{g}

m=\dfrac{1.9\ lb}{32\ ft/s^2}

m = 0.059 kg

2. (a) A 2300 kg rhinoceros, m = 2300 kg

W=2300\ kg\times 32\ ft/s^2=73600\ lb

(b) A 22 g song sparrow, m = 22 g = 0.022 kg

W=0.022\ kg\times 32\ ft/s^2=0.704\ lb

Hence, this is the required solution.

5 0
3 years ago
Other questions:
  • Describe the sequence of events in the lithification of a sandstone
    5·2 answers
  • If it takes Ashley 3 seconds to run from the batters box to first base at an average speed of 6.5 meters per second, what is the
    11·2 answers
  • Can some1 pls help me.
    9·1 answer
  • This is a textbook question, work too please!
    15·1 answer
  • What are simple machines please?
    13·2 answers
  • "When the ball leaves the ramp at Point B, students measure the horizontal" distance traveled. They repeat the experiment five t
    6·1 answer
  • I need help picture above
    10·1 answer
  • Please help
    8·1 answer
  • A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4. 5 m/s. What is the car’s change in momentum d
    15·1 answer
  • The average depth of water in a place near the coast of the Pacific ocean is 5.0 The largest tidal range in that place is 2.0m C
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!