Answer:
and
Step-by-step explanation:
The equation of the isotope decay is:
14-Carbon has a half-life of 5568 years, the time constant of the isotope is:
The decay time is:
(There is no a year 0 in chronology).
Lastly, the relative amount is estimated by direct substitution:
Answer:
1/100
Step-by-step explanation:
<u>Answer</u>
2,268
<u>Explanation</u>
<u>
</u>
<u>By grouping 378 ca</u>n be written as,
378 = 300 + 70 + 8
6× 378 = 6 × (300 + 70 + 8)
= (6×300)
+ (6×70) + (6×8)
= 1800
+ 420 + 48
= 2,268
Answer:
I can't see the choices but some options are:
36 subtract 3 = 33 subtract 3 = 30 subtract 3 = 27 subtract 3 = 24 subtract 3 = 21 subtract 3 = 18, etc.
Answer:
a. 0.9
b. 0.024
c. 0.06
d. 0.2
e. 0.336
Step-by-step explanation:
Since A, B and C are mutually exclusive then P (A U B U C)=P(A)+P(B)+P(C) and P(A∩B∩C)=P(A)*P(B)*P(C).
a.
P (A U B U C)=P(A)+P(B)+P(C)
P (A U B U C)=0.2+0.3+0.4=0.9
b.
P(A∩B∩C)=P(A)*P(B)*P(C)
P(A∩B∩C)=0.2*0.3*0.4=0.024
c.
P(A∩B)=P(A)*P(B)
P(A∩B)=0.2*0.3=0.06
d.
P[(AUB)∩C]=P(AUB)*P(C)
P(AUB)=P(A)+P(B)=0.2+0.3=0.5
P[(AUB)∩C]=0.5*0.4=0.20
e.
P(A')=1-P(A)=1-0.2=0.8
P(B')=1-P(B)=1-0.3=0.7
P(C')=1-P(C)=1-0.4=0.6
P(A'∩B'∩ C')=P(A')*P(B')*P(C')
P(A'∩B'∩ C')=0.8*0.7*0.6=0.336