Explanation:
It is given that,
Mas of the object, m = 6 kg
It is lifted through a distance, h = 5.25 m
Tension in the string, T = 80 N
(a) By considering the free body diagram of the object, the forces can be equated as :
Work done by tension, 
(b) Work done by gravity, 
(c) Let v is the final speed of the object and u = 0
v = 5.91 m/s
Hence, this is the required solution.
It's shows static electricity because of the hair
Answer:
Explanation:
Given:
- mass of the body stretching the spring,
- extension in spring,
- velocity of oscillation,
- initial displacement position of equilibrium,
<u>According to given:</u>
<u>we know frequency:</u>
Now, for position of mass in oscillation:
at 
∴
∵ at 
<h3>Question 1</h3>
Answer
option C) velocity
Explanation
acceleration = Δv ÷ Δt
<h3>Question 2</h3>
Answer
option C) m/s²
Explanation
Δv ÷ Δt
= m/s ÷ s
= m/s x 1/s
= m/s²
<h3>Question 3</h3>
Answer
option B) velocity has both direction and speed.
That is why velocity can be negative but speed can not and velocity is rate of change of displacement where as speed is rate of change of distance.
Constant = 8.314JK⁻¹mol⁻¹
T is for temperature which is 298K
Faraday constant value is 96500C/mol
n is the number of electrons which are transferred in the reaction.
Ecell = E₀cell - RT/nFiN [cathode]/[anode]
Ecell = E₀cell - RT/nF In [PH₂]/[H⁺]²
Ecell = 0.00-8.314 JK⁻¹ mol⁻¹ × 298k/ 2× 96500C/mol In [2.4atm]/ 0.70]²
Ecell = 0.00 - 0.0129 In (2.59)
Ecell = 0.00 - 0.0129 × 0.951
Ecell = -0.0122V
∴Ecell is = -o.0122v
