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Two identical ions are each missing two electrons, each ion has a charge of 2e. What is the magnitude of the force between the i

xz_007 [3.2K]

Answer:

|F| = 2.09 × 10⁻⁸ assuming that the two ions are point charges.

Explanation:

What's the charge on each ion?

The symbol $e$ here stands for fundamental charge. Each electron carries a negative fundamental charge of -e. Each proton carry a positive fundamental charge of +e.

Molecules and atoms are neutral. They contain an equal number of electrons and protons. Remove one electron from a molecule or atom, and that particle will end up with more protons (which are positive) than electrons. That particle will carry a positive charge of +e become an ion (a cation to be precise.) Remove another electron and the ion will carry a charge of +2e.

For each ion $q = +2 \;e = 2\times 1.60\times 10^{-19}\;\text{C} = 3.2\times 10^{-19}\;\text{C}$ .

What's the size of the electrostatic force between the two ions?

Consider Coulomb's Law for the electrostatic force $F$ between two point charges:

$\displaystyle F = -\frac{k\cdot q_1\cdot q_2}{r^{2}}$ ,

where

$k$ is Coulomb's constant,
$q_1$ and $q_2$ are the charge on the two point charges, and
$r$ is the separation between the two charges.

Make sure that all values are in SI units. Assume that the two ions are small enough that they act like point charges:

$\displaystyle \begin{aligned}F &= -\frac{k\cdot q_1 \cdot q_2}{r^{2}}\\&=-\frac{8.99\times 10^{9}\cdot(3.2\times 10^{-19}) \cdot (3.2\times 10^{-19})}{(2.1\times 10^{-10})^{2}}\\ &= -2.09\times 10^{-8}\;\text{N}\end{aligned}$ .

The value of $F$ is negative, meaning that the two charges will repel each other because they are both positive. The question is asking for the magnitude of this force. Thus drop the sign in front of $F$ to obtain $2.09\times 10^{-8}\;\text{N}$ , which is the magnitude of $F$ .

5 0

3 years ago

11) Which statement about covalent bonds is true? A) Covalent bonds are generally weaker than ionic bonds because they form full

Cerrena [4.2K]

<h3><u>Answer;</u></h3>

C) Covalent bonds are generally weaker than ionic bonds because they overlap electrons to fill their outer shell.

<h3><u>Explanation;</u></h3>

<em><u>Covalent bond is a type of bond that results from the sharing of electrons between two non-metal atoms. </u></em>
<em><u>Ionic bond on the other is a type of bond that results from the transfer of electrons between metal atoms and non metal atoms, where a metal atom looses electrons and a non-metal atom gains electrons.</u></em>
<em><u>The amount of energy required to break an given bond determines how strong a particular bond is.</u></em> Ionic bonds require more energy to break as compared to covalent bond and therefore they are stronger than the covalent bonds.

5 0

3 years ago

Read 2 more answers

Dave wishes to get produce from the store, which is a distance D- 2.2 km east of his house. Dave drives his bike to the store at

Neporo4naja [7]

Answer:

a) $t_1=338.4615\ s$

b) $t=1386.0805\ s$

c) $t=23.1013\ min$

d) $d=4400\ m$

e) Since Dave starts from house and finally returns to the house so displacement is zero.

Explanation:

Given:

distance between the house and the store, $s=2.2\ km=2200\ m$

speed of driving from house to store, $v_1=-6.5\ m.s^{-1}$

speed of driving back from store to house, $v_2=2.1\ m.s^{-1}$

Since the store is located towards east from his house and the velocity in this direction is taken negative and contrary to this the velocity in the west direction is taken positive.

a)

time taken in reaching the store:

$t_1=\frac{s}{v_1}$