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Lisa [10]
3 years ago
15

In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres o

f masses 1.56 kg and 21.1 g whose centers are separated by 5.34 cm. Calculate the gravitational force between these spheres, treating each as a point mass located at the center of the sphere. The value of the universal gravitational constant is 6.67259 × 10−11 N · m2 /kg2 .
Physics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

F = 7.7*10^{-10}N

Explanation:

You need to be careful with units for this problem. The force will be:

F =\frac{K*m1*m2}{d^2}

F=\frac{6.67259 * 10^{-11}*1.56*21.1*10^{-3}}{(5.34*10^{-2})^2}

F=7.7*10^{-10}N

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Answer:

When the volume increases or when the temperature decreases

Explanation:

The ideal gas equation states that:

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R is the gas constant

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Assuming that we have a fixed amount of gas, so n is constant, we can rewrite the equation as

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4 years ago
A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc
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Answer:

Approximately 28^{\circ}.

Explanation:

The refractive index of the air n_{\text{air}} is approximately 1.00.

Let n_\text{glass} denote the refractive index of the glass block, and let \theta _{\text{glass}} denote the angle of refraction in the glass. Let \theta_\text{air} denote the angle at which the light enters the glass block from the air.

By Snell's Law:

n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}}).

Rearrange the Snell's Law equation to obtain:

\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}.

Hence:

\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}.

In other words, the angle of refraction in the glass would be approximately 28^{\circ}.

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