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Aleksandr [31]
3 years ago
13

g decks to draw a specific card by a certain turn. For this problem you will be calculating the probability of drawing at least

one copy of a specific card by a given turn. Here's how our card game will be played 1. You will initially draw N cards from your deck. This is your starting hand 2. The next step is the mulligan. In the mulligan step you select between 0 and N cards to set aside. Let the number of cards you choose to set aside be M. You will then draw M more cards from the deck. 1. Note. You cannot redraw the cards you set aside because you set them aside and did not place them back into the deck 3. You then shuffle those cards back into the deck 4. After the initial draw and the mulligan you draw one card per turn. So now we want to calculate what are the odds that you will get at least one copy of the card you are looking for by the desired turn. Note that we are actually calculating the probability in this problem and
Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

can i get a picture

Step-by-step explanation:

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and negative = 240-360  = -120 degrees
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3 years ago
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4 0
3 years ago
y varies jointly as x and z. y equals 80y=80 when x equals 5x=5 and z equals 4z=4. Find y when x equals 4x=4 and z equals 6z=6.
Lubov Fominskaja [6]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \textit{\underline{y} varies jointly as \underline{x} and \underline{z}}\implies y=kxz
\\\\\\
\textit{we also know that }
\begin{cases}
y=80\\
x=5\\
z=4
\end{cases}\implies 80=k(5)(4)\implies 80=20k
\\\\\\
\cfrac{80}{20}=k\implies 4=k\qquad thus\qquad \boxed{y=4xz}\\\\
-------------------------------\\\\ if~\begin{cases}
x=4\\
z=6
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7 0
4 years ago
Y=2x-5 and goes through the point (1,4)
Ne4ueva [31]

Step-by-step explanation:

plug in 1 and 4 for x and y

(4)=2(1)-5

then do the math

4=2-5

4 does not equal -3 therefore it is not a solution

6 0
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