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2 years ago

8

Which equation represents a proportional relationship?

1 answer:

Aneli [31]2 years ago

7 0

And which is the equation?

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Finger [1]

The range of the function is $\{-19,-4,16\}$

Explanation:

The function is $f(n)=5n-4$

The domain of the function is $\{-3,0,4\}$

We need to find the range of the function.

The range can be determined by substituting the values of domain in the function.

Thus, the range of the function when the domain is -3 is given by

$f(-3)=5(-3)-4$

$=-15-4$

$=-19$

Thus, the range is -19 when $n=-3$

The range of the function when the domain is 0 is given by

$f(0)=5(0)-4$

$=0-4$

$=-4$

Thus, the range is -4 when $n=0$

The range of the function when the domain is 4 is given by

$f(4)=5(4)-4$

$=20-4$

$=16$

Thus, the range is 16 when $n=4$

Thus, the range of the function is $\{-19,-4,16\}$ when their corresponding domain is $\{-3,0,4\}$

Arranging the range in order from least to greatest is given by

$\{-19,-4,16\}$

Hence, the range of the function is $\{-19,-4,16\}$

6 0

3 years ago

Help WILL GIVE BRAINLIEST!! At the beginning of year 1, Carlos invested $600 at an annual compound interest rate of 4%. He makes

OleMash [197]

I got D but I use a diffrnt method

4 0

3 years ago

Read 2 more answers

Consider the given function and the given interval. f\(x\) = 2 sin\(x\) - sin\(2 x\) text(, ) [0 text(, ) pi] (a) Find the avera

Finger [1]

a. The average value of $f$ on the given interval is

$\displaystyle f_{\rm ave}=\frac1{\pi-0}\int_0^\pi(2\sin x-\sin2x)\,\mathrm dx=\boxed{\frac4\pi}$

b. Solve for $c$ :

$\dfrac4\pi=2\sin c-\sin2c\implies\boxed{c\approx1.238\text{ or }c\approx2.808}$

4 0

2 years ago

Help me with Thursday ASAP please

MrRissso [65]

Answer:

a + 3

Step-by-step explanation:

Kim's age is always three more than Tom's age.

7 0

3 years ago

Which of the following shows the prime factorization of 72 using exponential notation?

Luba_88 [7]

Answer:

2^3 .3^2

Step-by-step explanation:

if 2×2×2 = 8

and 3×3=9 then 8×9=72

6 0

3 years ago

Read 2 more answers