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Elena L [17]
3 years ago
8

Which equation represents a proportional relationship?

Mathematics
1 answer:
Aneli [31]3 years ago
7 0
And which is the equation?
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Can anyone please help i am stuck on this question?
ale4655 [162]

Answer:

8/17

General Formulas and Concepts:

<u>Trigonometry</u>

  • [Right Triangles Only] cos∅ = adjacent over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use trig to find the ratio.

<u>Step 2: Identify</u>

<em>POV from angle S</em>

Adjacent = 8

Hypotenuse = 17

<u>Step 3: Write</u>

  1. Substitute [cosine]:                    cos(s) = 8/17
5 0
3 years ago
Please Help Solve <br> 8 = 7/6 (b)
sukhopar [10]
B=48/7 you simplify 7/b(b) to 7b/6
Then multiply both sides by 6 so 8 x 6 =7b then simplify 8 x 6 =48
And divide both sides by 7 48\7 then switch sides b=48/7
4 0
3 years ago
Mia found the area of a polygon The area is 32 square cm.
solniwko [45]

Answer:

Only the isosceles trapezoid has an area of 32 cm².

Step-by-step explanation:

Let's calculate the area of each polygon.

For the two triangles we have:

A_{t} = \frac{bh}{2} = \frac{2 cm*4 cm}{2} = 4 cm^{2}

This polygon does not have an area of 32 cm².

For the rectangle we have:

A_{r} = bh = 6 cm*4 cm = 24 cm^{2}

This polygon does not have an area of 32 cm².

For the rectangle trapezoid we have:

A_{rt} = A_{t} + A_{r} = (4 + 24) cm^{2} = 28 cm^{2}

So, this polygon does not have an area of 32 cm².

Finally, for the isosceles trapezoid:

A_{it} = A_{t}*2 + A_{r} = (4*2 + 24) cm^{2} = 32 cm^{2}

This polygon does have an area of 32 cm².

   

Therefore, only the isosceles trapezoid has an area of 32 cm².

I hope it helps you!                              

8 0
3 years ago
I need help with range and domain ​
Katyanochek1 [597]

Answer:

69

Step-by-step explanation:

lol lol lol lol lol lol lol

4 0
3 years ago
How do you find the sine, cosine, and tangent values on the unit circle not in the first quadrant? Provide an example, and how y
gizmo_the_mogwai [7]
A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
  sin(α) = y = 0.6
  cos(α) = x = -0.8
  tan(α) = y/x = 0.6/-0.8 = -0.75

The angle is α = arccos(-0.8) ≈ 143.13°

______
For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.
7 0
3 years ago
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