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3 years ago

Solve for X If you have 2x+3

Mathematics

1 answer:

daser333 [38]3 years ago

5 0

Answer:

in the explanation

Step-by-step explanation:

According to the triangle midsegment theorem (if these points are midpoints),

2x + 3 is two times longer than 7, meaning it's 14.

2x+3=14

2x=11

x = 11/2

If there is an option for not enough info given, that should be right as it doesn't actually say that they are midpoints

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Someone please help me will give brainliest!!!!!

ololo11 [35]

I believe the fastest way to solve this problem is to take any two of the given points and to find the slope and y-intercept of the line connecting those two points.

Let's choose the 2 given points (-3,16) and (-1,12).
Going from the first point to the second, the increase in x is 2 and the increase in y is actually a decrease: -4. Thus, the slope of the line connecting these two points is m = -4/2, or m = -2.

Now use the slope-intercept formula to find the y-intercept, b.

One point on the line is (-3,16), and the slope is m = -2.

Thus, the slope-intercept formula y = mx + b becomes 16 = -2(-3) + b.
Here, b comes out to 10.

So now we have the slope and the y-intercept. Write the equation:

y = mx + b becomes y=-2x+10. Which of the four given answer choices is the correct one?

3 0

3 years ago

Simplify: ^4square root 400/ ^4square root 5 show your work

Rainbow [258]

⁴√400 / ⁴√5 = 400^¼ / 5^¼
= (5 x 2²)² / 5^¼
= 5² x 2⁴ / 5^¼
= ⁴√5^7 x 2⁴

7 0

3 years ago

A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn

tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

$(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)$

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.

The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

$\sigma = \dfrac{ 11}{\sqrt{121}} = 1$

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

$(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)$

That's probably the answer they're looking for.

4 0

3 years ago

You recently took a statistics exam in a large class. The instructor tells the class that the scores were Normally distributed,

Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

$X = 96, \mu = 72, \sigma = 12$