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kykrilka [37]
3 years ago
13

It's ya girl

Mathematics
2 answers:
Agata [3.3K]3 years ago
5 0

Answer:

oki! I hope you don't get banned! But if you come back, that's great! :)

Step-by-step explanation:

Misha Larkins [42]3 years ago
4 0

Answer:

thanks for the points i needed them

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Can someone please help me on this question and show the work if you can?
Studentka2010 [4]

Answer:

it is a 60 30 90 triangle so basically 2y is = x

21² + y² = x²

441 + y² = x²

y = x/2 (2y = x)

441 + x²/4 = x²

4x² = 1764 + x²

3x² = 1764

x = exact is 24.248711306 simplied square root would just be 14√3

2y = 14√3

y = 7√3

exact wouldd be 12.124355653

6 0
3 years ago
How do i solve this: |6y+2|=2|2y-1|
ziro4ka [17]

Answer:

Step-by-step explanation:

Group like terms 6y-2y= 2-1-2

When a number goes over the equal sign= positive + changes to negative, vice versa.

So final answer is 4y= -1= -4y

Because 4 is decided by -1

7 0
3 years ago
Read 2 more answers
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
Prove: An odd number squared is an odd number. = (2n + 1)2 ​
Mnenie [13.5K]

Answer:

{(2n + 1)}^{2}  = 4 {n}^{2}  + 4n + 1 = 2(2 {n}^{2}  + 2n) + 1

4 0
2 years ago
What is this I’m in a hurry please help :(
Nesterboy [21]
I'm pretty sure the answer is D bc it has the same coefficients and the same numbers
4 0
3 years ago
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