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Marina86 [1]
3 years ago
13

Hassan jogged 6 blocks then half that much again how many block did he jog for

Mathematics
1 answer:
malfutka [58]3 years ago
3 0

Answer:

3

Step-by-step explanation:

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prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact
Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable  on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that  limit property of an  integral

\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt

\int_{a}^{b} fdt=f(b)-f(a)....(Equation I)

Using above property of integral then we get

\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt......(Equation II)

Substitute equation I and equation II are equal

Then we get

\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}

\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)

\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)

Therefore, \int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt.

Hence, the value of function does not change after changing the value of function at c.

6 0
3 years ago
There are 156, 208 and 260 students in
irakobra [83]
156 = 2·2·3·13
208 = 2·2·2·2·13
260 = 2·2·5·13 
      = 2·2·13
      = 52
their gcf is 52, in 156 there are three 52, in 208 there are four 52, and in 260 there are five 52. So that there are minimum of twelve buses needed to be hired.
answer: 12
:)
5 0
3 years ago
Solve the proportion 7/5=21/x
Marysya12 [62]

Answer:

=15

Step-by-step explanation:

8 0
3 years ago
The ratio of on time departures to total departures from an airport durning a one-week period was 45-82. Write the ratio in frac
shutvik [7]
45/82, it would be this answer because the ratio form is 45:82, so it would the same order, but in fraction form.
6 0
3 years ago
What's the answer...I'm kinda lost
Lorico [155]
A reflection over the x axis means y valuable will be the opposite. C
4 0
3 years ago
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