Question

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.

Answer 1

Let t become the time he spent commuting on the first day of his vacation.

It is then calculated as $t + 2$.

$\to 40\times(t+2) = 60(t) + 20 \\\\\to 40t+80 = 60t + 20 \\\\\to 80-20 = 60t + 40t \\\\\to 60 = 20t \\\\\to t=\frac{60}{20} \\\\\to t=\frac{6}{2} \\\\\to t= 3$

It traveled $40\times (3 + 2) + 20 = 40\times 5 + 20 = 200+20=220$ miles on its first day of operation.

The car traveled $180\ miles$ on the second day, which was $60 \ miles \times 3$.

So,

Total mileage= first day traveled + second day traveled $= 220+ 180= 400 \miles$

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Total distance traveled: brainly.ph/question/11690847